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WBJEE Probability & Combinatorics Questions

Practise probability & combinatorics (mathematics) for the West Bengal Joint Entrance Examination: 10 multiple-choice questions, each with the correct answer and a worked explanation. Click an option to check it, or “New questions” for another set.

Probability & Combinatorics practice

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  1. Q1.In how many ways can a committee of 2 be chosen from 12 people?

    Show answer & explanation

    Answer: D — 66

    Order does not matter → combinations: 12C2 = 12! / (2!·10!) = 66.

  2. Q2.In how many ways can the letters of the word TABLE be arranged?

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    Answer: C — 120

    All 5 letters are different, so arrangements = 5! = 120.

  3. Q3.A card is drawn from a well-shuffled deck of 52. What is the probability that it is an ace or a king?

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    Answer: B — 2/13

    There are 8 such cards in 52, so P = 8/52 = 2/13.

  4. Q4.4 fair coins are tossed. What is the probability of at least one head?

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    Answer: D — 15/16

    P(no head) = (1/2)^4 = 1/16; P(at least one head) = 1 − 1/16 = 15/16.

  5. Q5.In how many ways can a committee of 3 be chosen from 12 people?

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    Answer: A — 220

    Order does not matter → combinations: 12C3 = 12! / (3!·9!) = 220.

  6. Q6.In how many ways can a committee of 3 be chosen from 8 people?

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    Answer: D — 56

    Order does not matter → combinations: 8C3 = 8! / (3!·5!) = 56.

  7. Q7.3 fair coins are tossed. What is the probability of at least one head?

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    Answer: A — 7/8

    P(no head) = (1/2)^3 = 1/8; P(at least one head) = 1 − 1/8 = 7/8.

  8. Q8.In how many ways can the letters of the word GARDEN be arranged?

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    Answer: C — 720

    All 6 letters are different, so arrangements = 6! = 720.

  9. Q9.In how many ways can the letters of the word MOTHER be arranged?

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    Answer: C — 720

    All 6 letters are different, so arrangements = 6! = 720.

  10. Q10.2 fair coins are tossed. What is the probability of at least one head?

    Show answer & explanation

    Answer: A — 3/4

    P(no head) = (1/2)^2 = 1/4; P(at least one head) = 1 − 1/4 = 3/4.

Free WBJEE Probability & Combinatorics Questions by pGento

How to approach probability & combinatorics questions

Probability = favourable ÷ total outcomes. List small sample spaces (two dice = 36 outcomes). Use nPr when order matters and nCr when it does not; divide by repeats for repeated letters.

About WBJEE

West Bengal Joint Entrance Examination — conducted by West Bengal Joint Entrance Examinations Board (WBJEEB). State engineering, technology and pharmacy entrance for West Bengal.

Original practice questions written for this site in the style and difficulty of each exam’s syllabus. They are not past papers and the site is not affiliated with any exam body. Exam patterns, marking schemes and syllabi change — always check the latest official notification.

WBJEE practice topics

TopicSectionQuestion source
AlgebraMathematicsCalculated (new numbers every set)
Probability & CombinatoricsMathematicsCalculated (new numbers every set)
PhysicsScienceCalculated + question bank
ChemistryScienceCalculated + question bank

Frequently asked questions

In how many ways can a committee of 2 be chosen from 12 people?
Answer: D — 66. Order does not matter → combinations: 12C2 = 12! / (2!·10!) = 66.
In how many ways can the letters of the word TABLE be arranged?
Answer: C — 120. All 5 letters are different, so arrangements = 5! = 120.
A card is drawn from a well-shuffled deck of 52. What is the probability that it is an ace or a king?
Answer: B — 2/13. There are 8 such cards in 52, so P = 8/52 = 2/13.
Are these real past exam papers?
No. Every question is an original practice question written in the style, syllabus and difficulty of the exam, with a worked explanation. The site is not affiliated with any exam body.
WBJEE Probability & Combinatorics Questions

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