Skip to content
  • No data uploaded
  • Instant results

UGC NET Paper 1 Averages & Statistics Questions

Practise averages & statistics (quantitative aptitude) for the UGC National Eligibility Test (Paper 1): 10 multiple-choice questions, each with the correct answer and a worked explanation. Click an option to check it, or “New questions” for another set.

Averages & Statistics practice

0 / 10 answered Take a timed mock test
  1. Q1.The average of 9 numbers is 46. If 83 is added, what is the new average?

    Show answer & explanation

    Answer: B — 49.7

    Old total = 9 × 46 = 414. New total = 414 + 83 = 497; new average = 497/10 = 49.7.

  2. Q2.Find the mean of: 16, 21, 15, 3, 37, 40, 14

    Show answer & explanation

    Answer: D — 20.86

    Sum = 146, ÷ 7 = 20.86.

  3. Q3.Find the range of: 19, 11, 39, 5, 28, 24, 4

    Show answer & explanation

    Answer: C — 35

    Range = max − min = 39 − 4 = 35.

  4. Q4.Find the mean of: 7, 9, 11, 38, 26, 40, 35

    Show answer & explanation

    Answer: D — 23.71

    Sum = 166, ÷ 7 = 23.71.

  5. Q5.Find the mean of: 24, 15, 36, 15, 32, 25, 5

    Show answer & explanation

    Answer: A — 21.71

    Sum = 152, ÷ 7 = 21.71.

  6. Q6.The average of 5 numbers is 34. If 49 is added, what is the new average?

    Show answer & explanation

    Answer: A — 36.5

    Old total = 5 × 34 = 170. New total = 170 + 49 = 219; new average = 219/6 = 36.5.

  7. Q7.The average of 7 numbers is 56. If 68 is added, what is the new average?

    Show answer & explanation

    Answer: B — 57.5

    Old total = 7 × 56 = 392. New total = 392 + 68 = 460; new average = 460/8 = 57.5.

  8. Q8.Find the range of: 16, 2, 3, 27, 30, 34, 8

    Show answer & explanation

    Answer: A — 32

    Range = max − min = 34 − 2 = 32.

  9. Q9.The average of 10 numbers is 79. If 110 is added, what is the new average?

    Show answer & explanation

    Answer: B — 81.82

    Old total = 10 × 79 = 790. New total = 790 + 110 = 900; new average = 900/11 = 81.82.

  10. Q10.Find the mean of: 7, 26, 23, 31, 24, 2, 9

    Show answer & explanation

    Answer: C — 17.43

    Sum = 122, ÷ 7 = 17.43.

Free UGC NET Paper 1 Averages & Statistics Questions by pGento

How to approach averages & statistics questions

Average × count = total: most average questions are really about totals. For a set of data, sort it before finding the median and look for the most frequent value for the mode.

About UGC NET Paper 1

UGC National Eligibility Test (Paper 1) — conducted by National Testing Agency (NTA). Qualifies candidates for Assistant Professor and JRF; Paper 1 tests teaching and research aptitude.

Original practice questions written for this site in the style and difficulty of each exam’s syllabus. They are not past papers and the site is not affiliated with any exam body. Exam patterns, marking schemes and syllabi change — always check the latest official notification.

UGC NET Paper 1 practice topics

TopicSectionQuestion source
Logical ReasoningReasoningCalculated (new numbers every set)
Data InterpretationData interpretationCalculated (new numbers every set)
Computer AwarenessComputer knowledgeQuestion bank
Averages & StatisticsQuantitative aptitudeCalculated (new numbers every set)

Frequently asked questions

The average of 9 numbers is 46. If 83 is added, what is the new average?
Answer: B — 49.7. Old total = 9 × 46 = 414. New total = 414 + 83 = 497; new average = 497/10 = 49.7.
Find the mean of: 16, 21, 15, 3, 37, 40, 14
Answer: D — 20.86. Sum = 146, ÷ 7 = 20.86.
Find the range of: 19, 11, 39, 5, 28, 24, 4
Answer: C — 35. Range = max − min = 39 − 4 = 35.
Are these real past exam papers?
No. Every question is an original practice question written in the style, syllabus and difficulty of the exam, with a worked explanation. The site is not affiliated with any exam body.
UGC NET Paper 1 Averages & Statistics Questions

Embed this tool on your site

Paste this code into any web page. It stays free, fast and ad-free inside your site.

Print or save as PDF

Prints just this tool and its result. Choose “Save as PDF” as the printer to get a file. Branding is stored only in this browser.