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KCET Geometry & Mensuration Questions

Practise geometry & mensuration (mathematics) for the Karnataka Common Entrance Test: 10 multiple-choice questions, each with the correct answer and a worked explanation. Click an option to check it, or “New questions” for another set.

Geometry & Mensuration practice

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  1. Q1.Find the distance between (4, -3) and (10, 5).

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    Answer: B — 10

    Distance = √((Δx)² + (Δy)²) = √(6² + 8²) = 10.

  2. Q2.A right triangle has legs 8 cm and 15 cm. Find the hypotenuse.

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    Answer: B — 17 cm

    By Pythagoras, hypotenuse = √(8² + 15²) = √289 = 17.

  3. Q3.Find the distance between (4, -4) and (9, 8).

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    Answer: C — 13

    Distance = √((Δx)² + (Δy)²) = √(5² + 12²) = 13.

  4. Q4.A right triangle has legs 6 cm and 8 cm. Find the hypotenuse.

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    Answer: C — 10 cm

    By Pythagoras, hypotenuse = √(6² + 8²) = √100 = 10.

  5. Q5.Find the volume of a cylinder with radius 14 cm and height 4 cm (take π = 22/7).

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    Answer: A — 2,464 cm³

    Using πr²h with π = 22/7: 2,464 cm³.

  6. Q6.Find the area of a circle of radius 14 cm (take π = 22/7).

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    Answer: B — 616 cm²

    Using πr² with π = 22/7: 616 cm².

  7. Q7.Find the volume of a sphere of radius 7 cm (take π = 22/7).

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    Answer: B — 1,437.33 cm³

    Using (4/3)πr³ with π = 22/7: 1,437.33 cm³.

  8. Q8.Find the distance between (4, 4) and (9, 16).

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    Answer: A — 13

    Distance = √((Δx)² + (Δy)²) = √(5² + 12²) = 13.

  9. Q9.A right triangle has legs 3 cm and 4 cm. Find the hypotenuse.

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    Answer: D — 5 cm

    By Pythagoras, hypotenuse = √(3² + 4²) = √25 = 5.

  10. Q10.Find the distance between (-4, -2) and (4, 13).

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    Answer: B — 17

    Distance = √((Δx)² + (Δy)²) = √(8² + 15²) = 17.

Free KCET Geometry & Mensuration Questions by pGento

How to approach geometry & mensuration questions

Memorise core formulas (circle πr², triangle ½bh, Pythagoras, distance √((x₂−x₁)² + (y₂−y₁)²)). Sketch the figure — most errors come from misreading which length is given.

About KCET

Karnataka Common Entrance Test — conducted by Karnataka Examinations Authority (KEA). State entrance for professional courses in Karnataka.

Original practice questions written for this site in the style and difficulty of each exam’s syllabus. They are not past papers and the site is not affiliated with any exam body. Exam patterns, marking schemes and syllabi change — always check the latest official notification.

KCET practice topics

TopicSectionQuestion source
AlgebraMathematicsCalculated (new numbers every set)
Geometry & MensurationMathematicsCalculated (new numbers every set)
PhysicsScienceCalculated + question bank
ChemistryScienceCalculated + question bank
BiologyScienceQuestion bank

Frequently asked questions

Find the distance between (4, -3) and (10, 5).
Answer: B — 10. Distance = √((Δx)² + (Δy)²) = √(6² + 8²) = 10.
A right triangle has legs 8 cm and 15 cm. Find the hypotenuse.
Answer: B — 17 cm. By Pythagoras, hypotenuse = √(8² + 15²) = √289 = 17.
Find the distance between (4, -4) and (9, 8).
Answer: C — 13. Distance = √((Δx)² + (Δy)²) = √(5² + 12²) = 13.
Are these real past exam papers?
No. Every question is an original practice question written in the style, syllabus and difficulty of the exam, with a worked explanation. The site is not affiliated with any exam body.
KCET Geometry & Mensuration Questions

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