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JEE Advanced Algebra Questions

Practise algebra (mathematics) for the Joint Entrance Examination (Advanced): 10 multiple-choice questions, each with the correct answer and a worked explanation. Click an option to check it, or “New questions” for another set.

Algebra practice

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  1. Q1.Solve: 3x + 2y = 31 and x + 4y = 17

    Show answer & explanation

    Answer: B — x = 9, y = 2

    Elimination/substitution gives x = 9, y = 2. Check: 3(9) + 2(2) = 31 ✓ and 1(9) + 4(2) = 17 ✓.

  2. Q2.Find log 1,000,000 (base 10).

    Show answer & explanation

    Answer: D — 6

    log_10(1000000) asks “10 to what power gives 1000000?” → 10^6 = 1000000, so the answer is 6.

  3. Q3.Find log₅ 3,125.

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    Answer: D — 5

    log_5(3125) asks “5 to what power gives 3125?” → 5^5 = 3125, so the answer is 5.

  4. Q4.Solve: x + 2y = 8 and 4x + y = 4

    Show answer & explanation

    Answer: D — x = 0, y = 4

    Elimination/substitution gives x = 0, y = 4. Check: 1(0) + 2(4) = 8 ✓ and 4(0) + 1(4) = 4 ✓.

  5. Q5.Find the sum of the first 14 terms of the AP 17, 26, 35, …

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    Answer: C — 1057

    Sₙ = n/2 × [2a + (n − 1)d] = 14/2 × [34 + 117] = 1,057.

  6. Q6.Solve: x² + 11x + 24 = 0

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    Answer: D — -8, -3

    Find two roots with sum -11 and product 24: -3 and -8. So x² + 11x + 24 = (x + 3)(x + 8) = 0.

  7. Q7.Solve: x² + 13x + 36 = 0

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    Answer: A — -9, -4

    Find two roots with sum -13 and product 36: -4 and -9. So x² + 13x + 36 = (x + 4)(x + 9) = 0.

  8. Q8.Solve: x² + 6x + 5 = 0

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    Answer: A — -5, -1

    Find two roots with sum -6 and product 5: -5 and -1. So x² + 6x + 5 = (x + 5)(x + 1) = 0.

  9. Q9.Solve: x² + 3x + 2 = 0

    Show answer & explanation

    Answer: C — -2, -1

    Find two roots with sum -3 and product 2: -2 and -1. So x² + 3x + 2 = (x + 2)(x + 1) = 0.

  10. Q10.Solve: 2x + 3y = 23 and 4x + 4y = 24

    Show answer & explanation

    Answer: D — x = -5, y = 11

    Elimination/substitution gives x = -5, y = 11. Check: 2(-5) + 3(11) = 23 ✓ and 4(-5) + 4(11) = 24 ✓.

Free JEE Advanced Algebra Questions by pGento

How to approach algebra questions

Factorise quadratics by finding two numbers with the right sum and product; check roots by substitution. For simultaneous equations, elimination is usually faster than substitution under time pressure.

About JEE Advanced

Joint Entrance Examination (Advanced) — conducted by IITs (organising IIT rotates each year). The entrance exam for undergraduate programmes at the Indian Institutes of Technology.

Original practice questions written for this site in the style and difficulty of each exam’s syllabus. They are not past papers and the site is not affiliated with any exam body. Exam patterns, marking schemes and syllabi change — always check the latest official notification.

JEE Advanced practice topics

TopicSectionQuestion source
AlgebraMathematicsCalculated (new numbers every set)
Probability & CombinatoricsMathematicsCalculated (new numbers every set)
Geometry & MensurationMathematicsCalculated (new numbers every set)
PhysicsScienceCalculated + question bank
ChemistryScienceCalculated + question bank

Frequently asked questions

Solve: 3x + 2y = 31 and x + 4y = 17
Answer: B — x = 9, y = 2. Elimination/substitution gives x = 9, y = 2. Check: 3(9) + 2(2) = 31 ✓ and 1(9) + 4(2) = 17 ✓.
Find log 1,000,000 (base 10).
Answer: D — 6. log_10(1000000) asks “10 to what power gives 1000000?” → 10^6 = 1000000, so the answer is 6.
Find log₅ 3,125.
Answer: D — 5. log_5(3125) asks “5 to what power gives 3125?” → 5^5 = 3125, so the answer is 5.
Are these real past exam papers?
No. Every question is an original practice question written in the style, syllabus and difficulty of the exam, with a worked explanation. The site is not affiliated with any exam body.
JEE Advanced Algebra Questions

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