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BITSAT Chemistry Questions

Practise chemistry (science) for the BITS Admission Test: 10 multiple-choice questions, each with the correct answer and a worked explanation. Click an option to check it, or “New questions” for another set.

Chemistry practice

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  1. Q1.Which bond is formed by the sharing of electrons?

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    Answer: B — Covalent

    Covalent bonds share electron pairs.

  2. Q2.58.5 g of KCl (molar mass 74.5) is dissolved to make 250 mL of solution. Find the molarity.

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    Answer: C — 3.141 M

    Moles = 58.5/74.5 = 0.785; molarity = moles ÷ litres = 0.785 ÷ 0.25 = 3.141 M.

  3. Q3.Avogadro’s number is approximately:

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    Answer: A — 6.022 × 10²³

    One mole contains 6.022 × 10²³ particles.

  4. Q4.What is the mass of 2.5 mol of water (H₂O)? (Molar mass 18 g/mol)

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    Answer: B — 45 g

    Mass = moles × molar mass = 2.5 × 18 g/mol = 45 g.

  5. Q5.Which gas is produced when zinc reacts with dilute hydrochloric acid?

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    Answer: D — Hydrogen

    Zn + 2HCl → ZnCl₂ + H₂.

  6. Q6.What is the pH of a solution with [H⁺] = 10⁻¹ mol/L?

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    Answer: C — 1

    pH = −log[H⁺] = −log(10⁻¹) = 1.

  7. Q7.The periodic table is arranged in order of increasing:

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    Answer: B — Atomic number

    The modern periodic table orders elements by atomic number.

  8. Q8.What is the mass of 0.5 mol of water (H₂O)? (Molar mass 18 g/mol)

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    Answer: B — 9 g

    Mass = moles × molar mass = 0.5 × 18 g/mol = 9 g.

  9. Q9.Which is the most electronegative element?

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    Answer: B — Fluorine

    Fluorine has the highest electronegativity (3.98 on the Pauling scale).

  10. Q10.10 g of KCl (molar mass 74.5) is dissolved to make 1000 mL of solution. Find the molarity.

    Show answer & explanation

    Answer: C — 0.134 M

    Moles = 10/74.5 = 0.134; molarity = moles ÷ litres = 0.134 ÷ 1 = 0.134 M.

Free BITSAT Chemistry Questions by pGento

How to approach chemistry questions

Moles = mass ÷ molar mass; molarity = moles ÷ litres. pH = −log[H⁺] and pH + pOH = 14 at 25 °C. For concepts, link each property to its position in the periodic table.

About BITSAT

BITS Admission Test — conducted by Birla Institute of Technology and Science (BITS), Pilani. Online admission test for BITS Pilani, Goa and Hyderabad campuses.

Original practice questions written for this site in the style and difficulty of each exam’s syllabus. They are not past papers and the site is not affiliated with any exam body. Exam patterns, marking schemes and syllabi change — always check the latest official notification.

BITSAT practice topics

TopicSectionQuestion source
AlgebraMathematicsCalculated (new numbers every set)
PhysicsScienceCalculated + question bank
ChemistryScienceCalculated + question bank
English GrammarEnglishQuestion bank
Logical ReasoningReasoningCalculated (new numbers every set)

Frequently asked questions

Which bond is formed by the sharing of electrons?
Answer: B — Covalent. Covalent bonds share electron pairs.
58.5 g of KCl (molar mass 74.5) is dissolved to make 250 mL of solution. Find the molarity.
Answer: C — 3.141 M. Moles = 58.5/74.5 = 0.785; molarity = moles ÷ litres = 0.785 ÷ 0.25 = 3.141 M.
Avogadro’s number is approximately:
Answer: A — 6.022 × 10²³. One mole contains 6.022 × 10²³ particles.
Are these real past exam papers?
No. Every question is an original practice question written in the style, syllabus and difficulty of the exam, with a worked explanation. The site is not affiliated with any exam body.
BITSAT Chemistry Questions

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