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ACT Probability & Combinatorics Questions

Practise probability & combinatorics (mathematics) for the ACT: 10 multiple-choice questions, each with the correct answer and a worked explanation. Click an option to check it, or “New questions” for another set.

Probability & Combinatorics practice

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  1. Q1.In how many ways can the letters of the word GARDEN be arranged?

    Show answer & explanation

    Answer: A — 720

    All 6 letters are different, so arrangements = 6! = 720.

  2. Q2.In how many ways can the letters of the word PENCIL be arranged?

    Show answer & explanation

    Answer: A — 720

    All 6 letters are different, so arrangements = 6! = 720.

  3. Q3.4 fair coins are tossed. What is the probability of at least one head?

    Show answer & explanation

    Answer: A — 15/16

    P(no head) = (1/2)^4 = 1/16; P(at least one head) = 1 − 1/16 = 15/16.

  4. Q4.In how many ways can a committee of 4 be chosen from 12 people?

    Show answer & explanation

    Answer: C — 495

    Order does not matter → combinations: 12C4 = 12! / (4!·8!) = 495.

  5. Q5.2 fair coins are tossed. What is the probability of at least one head?

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    Answer: B — 3/4

    P(no head) = (1/2)^2 = 1/4; P(at least one head) = 1 − 1/4 = 3/4.

  6. Q6.In how many ways can the letters of the word MOTHER be arranged?

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    Answer: B — 720

    All 6 letters are different, so arrangements = 6! = 720.

  7. Q7.Two fair dice are thrown. What is the probability that the sum is 6?

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    Answer: B — 5/36

    5 of the 36 equally likely outcomes give a sum of 6, so P = 5/36 = 5/36.

  8. Q8.A card is drawn from a well-shuffled deck of 52. What is the probability that it is a red card?

    Show answer & explanation

    Answer: C — 1/2

    There are 26 such cards in 52, so P = 26/52 = 1/2.

  9. Q9.A card is drawn from a well-shuffled deck of 52. What is the probability that it is a heart?

    Show answer & explanation

    Answer: C — 1/4

    There are 13 such cards in 52, so P = 13/52 = 1/4.

  10. Q10.A card is drawn from a well-shuffled deck of 52. What is the probability that it is an ace or a king?

    Show answer & explanation

    Answer: A — 2/13

    There are 8 such cards in 52, so P = 8/52 = 2/13.

Free ACT Probability & Combinatorics Questions by pGento

How to approach probability & combinatorics questions

Probability = favourable ÷ total outcomes. List small sample spaces (two dice = 36 outcomes). Use nPr when order matters and nCr when it does not; divide by repeats for repeated letters.

About ACT

ACT — conducted by ACT, Inc.. US college admission test with English, Math and Reading, plus an optional Science section.

Original practice questions written for this site in the style and difficulty of each exam’s syllabus. They are not past papers and the site is not affiliated with any exam body. Exam patterns, marking schemes and syllabi change — always check the latest official notification.

ACT practice topics

TopicSectionQuestion source
AlgebraMathematicsCalculated (new numbers every set)
Geometry & MensurationMathematicsCalculated (new numbers every set)
Probability & CombinatoricsMathematicsCalculated (new numbers every set)
English GrammarEnglishQuestion bank
PhysicsScienceCalculated + question bank
ChemistryScienceCalculated + question bank

Frequently asked questions

In how many ways can the letters of the word GARDEN be arranged?
Answer: A — 720. All 6 letters are different, so arrangements = 6! = 720.
In how many ways can the letters of the word PENCIL be arranged?
Answer: A — 720. All 6 letters are different, so arrangements = 6! = 720.
4 fair coins are tossed. What is the probability of at least one head?
Answer: A — 15/16. P(no head) = (1/2)^4 = 1/16; P(at least one head) = 1 − 1/16 = 15/16.
Are these real past exam papers?
No. Every question is an original practice question written in the style, syllabus and difficulty of the exam, with a worked explanation. The site is not affiliated with any exam body.
ACT Probability & Combinatorics Questions

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